seb ) wrote:
(Ben Rotter) wrote in message . com>...
>
>> It means you'll get ~58% *total* SO2. Some of that will then become
>> free, and some will become bound (total = bound + free).

>Ben, here a quote from the winemakermag :

>"The key question now is: How much free SO2 is really added for any
>given amount of sulfite? Potassium metabisulfite and Campden tablets
>consist of approximately 57 percent and 48 percent SO2, respectively.
>This means that roughly half of the sulfite actually becomes free SO2
>when a solution is prepared and added to wine."

>Thanks for your link, I had already read it and many more about SO2
>but I read different things about the 57% explanation. That's the
>only part i can't be sure of.

>Séb

Hi,

It's easy enough to calculate for yourself. Meta is just K2S2O5,
and the molecular weights of K, S, and O are 39, 32, and 16,
repsectively. Find the total weight, and divide it into the weight
of the 2 SO2 molecules you get from each meta molecule.

Voila! 57%.

:-)

Dave
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Dave Breeden