You can tell I'm not a chemist. The Wine Thief article was using a test
kit and there wasn't any info on the chemicals used, just how much NAOH
had been used so I felt that this was probably why it was different.
Both you and Jeff Cox specify the .1N NAOH but he used a 15ml sample.
Because it was said that dilution of the material if red wine was OK to
do to make it easier to read, I didn't pick up on the sample size
difference.

Sorry I quoted your multiple wrong. I realized that I'd put the . in
the wrong place as I hit send. Thanks for the help.

Dick



Lum Eisenman wrote:
> Dick,
> There are two variables. The size of the wine sample and the
> "normality" of the sodium hydroxide.
> If a 5 ml wine sample and if the normality of the sodium hydroxide is
> 0.1, then the TA equals the amount of sodium hydroxide in milliliters
> used in the titration multiplied by 0.15.
> Lum
>
> "Dick Heckman" > wrote in message
> ...
>> I'm confused. I've read 3 test procedures and gotten 3 ways to do the
>> test. Lum says to multiply the ml of naoh by 1.5. Jeff Cox says
>> divide by 2 and somebody posted a procedure here from the Wine Thief
>> which I copied some time ago which says the the amount used is the TA
>> in ml/1000. Help!
>>
>> Dick
>