Dick,
There are two variables. The size of the wine sample and the "normality" of
the sodium hydroxide.
If a 5 ml wine sample and if the normality of the sodium hydroxide is 0.1,
then the TA equals the amount of sodium hydroxide in milliliters used in the
titration multiplied by 0.15.
Lum

"Dick Heckman" > wrote in message
...
> I'm confused. I've read 3 test procedures and gotten 3 ways to do the
> test. Lum says to multiply the ml of naoh by 1.5. Jeff Cox says divide by
> 2 and somebody posted a procedure here from the Wine Thief which I copied
> some time ago which says the the amount used is the TA in ml/1000. Help!
>
> Dick